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The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with a solution of 2 M sucrose and 1 M glucose. Side B is half-filled with 1 M sucrose and 2 M glucose. Initially, the liquid levels on both sides are equal.

Answer :

akmalyounas

Answer:

Intially the glucose concentration is levelled and then the liquid level in side A will rise.

Explanation:

  • Initially the liquid ob both sides are in isotonic condition.
  • The membrane is permeable to glucose so glucose will diffuse from higher concentration (2 M) to lower concentration (1 M) until the concentration become equal (1.5 M) on both sides.
  • Know, the Side A have 2 M sucrose and 1.5 M glucose and  side B have 1 M glucose and 1 M sucrose.
  • The side A will become hypertonic and side B will become hypotonic and water will start moving from side B to side A.

The U-tube is permeable to both water and glucose due to its smaller molecular size but not sucrose which is a large molecule.

There is unequal concentration of water and glucose on both sides of the tube so the water and glucose molecules move from a level of higher concentration to the area of lower concentration until both are equal in concentration.

But the levels of sucrose remain unequal due to no movement across the membrane so we can conclude that in U-tube the concentration of both water and glucose will be equal on both sides.

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