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For the reaction given below, the frequency factor A is 8.7 10¹² s⁻¹ and the activation energy is 63 kJ/mol.
[tex]NO(g) + O_3(g) \rightarrow NO_2(g) + O_2(g)[/tex]
What is the rate constant for the reaction at 95°C?

Answer :

Answer:

K = 9940

Explanation:

So we were given the following:

Activation energy (Ea) = 63 kJ/mol = 63000 J/mol

Frequency Factor (A) = 8.7 10¹² s⁻¹

Temperature = 95 + 273 = 368 K (Converting to Kelvin unit)

Rate constant (K) = ?

The formular relating all these parameters is;

K = A e-(Ea / RT)

where k represents the rate constant, Ea is the activation energy, R is the gas constant (8.3145 J/K mol), and T is the temperature expressed in Kelvin. A is known as the frequency factor, having units of L mol-1 s-1

Inserting the values, we have;

K = 8.7 x 10¹² x e-(63000 / (8.3145 x 368) )

K = 9940

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