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a laboratory employee is mixing a 10% saline solution with a 4% saline solution. how much of each solution is needed to make 500 ml of a 6% solution​

Answer :

Answer:

Step-by-step explanation:

let he 10 % solution =x ml

0.1 0 x+(500-x)×0.04=500×0.06

0.10 x+20-0.04 x=30

0.06 x=30-20

0.06 x=10

x=10/(0.06)=1000/6=500/3 ml=166  2/3 ml

so 10 % solution is 166  2/3  ml

4 % solution=500 -500/3=1000/3=333 1/3 ml

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