Answered

HELP ASAP WILL GIVE BRAINLIEST
State the restrictions on the domain of the function.
f(x)=1x-7

x≠0

x≠-7

x≠7

x≠-1

x≠1
State the restrictions on the domain of the function.
f(x)=(x+7)(x-9)(x-3)(x+7)

x≠-3 or 7

x≠3 or 9

x≠3 or -7 or 9

x≠3 or -7

x≠-3 or -9
x≠-3 or -9

Answer :

kudzordzifrancis

Answer:

1) x≠7

2) x≠3 or -7

Step-by-step explanation:

1. The given function is

[tex]f(x) = \frac{1}{x - 7} [/tex]

This function is undefined if the denominator is equal to zero .

Therefore the restriction is that:

The denominator is not zero.

[tex]x - 7 \ne0[/tex]

[tex]x \ne7[/tex]

2) Assuming the second function is

[tex]f(x) = \frac{(x + 7)(x - 9)}{(x - 3)(x + 7)} [/tex]

This function is not defined when the denominator is zero.

This implies that:

[tex](x - 3)(x + 7) \ne0[/tex]

The restrictions are:

[tex]x \ne3 \: or \: - 7[/tex]

Other Questions