YuiSnow
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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Find m∠R.

Write your answer as an integer or as a decimal rounded to the nearest tenth.


m∠R = °

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!! Find m∠R. Write your answer as an integer or as a decimal rounded to the nearest tenth. m∠R = ° class=

Answer :

luisejr77

Answer: [tex]m\angle R=77.2\°[/tex]

Step-by-step explanation:

For this exercise you need to use an Inverse Trigonometric Function called "Arctangent".

By definition:

[tex]\alpha =arctan(\frac{opposite}{adjacent})[/tex]

You must observe carefully the triangle PQR shown in the picture attached.

In this case you can identify that:

[tex]\alpha=m\angle R\\\\opposite=PQ=8\\\\adjacent=QR=3[/tex]

Therefore, knowing those values you can substitute them into  [tex]\alpha =arctan(\frac{opposite}{adjacent})[/tex] , as following:

 [tex]m\angle R=arctan(\frac{PQ}{QR})\\\\m\angle R=arctan(\frac{8}{3})[/tex]

Finally, evaluating, you get that the measure of the angle R is the following:

[tex]m\angle R=77.15\°[/tex]

Rounding to the nearest tenth:

[tex]m\angle R\approx77.2\°[/tex]

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