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Two pipes simultaneously vibrate with their fundamental frequencies, one at 400 Hz and another at 800 Hz. Each pipe can be either an open-open or an open-closed pipe. Assume that the speed of sound in air is 340 m/s. Determine the length of the pipes if you know that the pipes have equal lengths.

Answer :

Answer:

Explanation:

Given

Two Fundamental frequencies are 400 Hz and 800 Hz

Each Pipe has same length L

Fundamental frequency corresponding to pipe with both side open

[tex]f_0_{opn}=\frac{v}{2L}[/tex]

where v=velocity of sound

Fundamental frequency corresponding to pipe with one side open and other side close

[tex]f_0_{close}=\frac{v}{4L}[/tex]

we can see that fundamental frequency of both side open pipe is twice of second pipe

so 800 Hz frequency will correspond to both side open pipe

[tex]800=\frac{340}{2\cdot L}[/tex]

[tex]L=0.2125\ m[/tex]

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