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A bat, flying at 7.00 m/s toward a wall, emits a chirp at 50.0 kHz. If the wall reflects this sound pulse, what is the frequency of the echo received by the bat? (vsound = 340 m/s)

Answer :

Answer:

Explanation:

Given

Velocity of bat [tex]v_o=7\ m/s[/tex]

Frequency of sound [tex]f=50\ kHz[/tex]

velocity of sound [tex]v=340\ m/s[/tex]

using Doppler Effect apparent frequency is given by

[tex]f'=f\cdot \frac{v-v_o}{v+v_s}[/tex]

where  

[tex]f'=[/tex]apparent frequency  

v=velocity of sound in the given media

[tex]v_s=[/tex]velocity of source

[tex]v_o=[/tex]velocity of observer      

here velocity of source is zero

as source is travelling towards source thus

[tex]f'=50\cdot (\frac{340+7}{340})[/tex]

[tex]f'=51.029\ Hz[/tex]                            

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