Answer :
Answer:
Moves to the right
Explanation:
Given:
- Right side @ x = 5 cm is at - 100 V
- Left side @ x = 0 cm is at 300 V
- Charge is placed @ x = 2.5 cm
Find:
- The direction of motion of + charge when released from its position.
Solution:
- We know that Electric field is always perpendicular to equi-potential lines. Hence it points out from the left side towards the right hand side. So the Electric field at the point of charge @ x = 2.5 cm, is directed towards the right that would also be the direction of motion of the positive charge.
Answer:
The charge will move to the right.
Explanation:
The electric potential is defined as the work per unit of charge necessary to move a charge from a point to another one.
Electric charges move to different zones of ponential depending on their charge: negative charges move from lower to higher potentials. Positive charges move from higher to lower potentials.
Since the highest potential is at x=0 (left) and lowest at x=5 (right) and the charge is positive, it will move to the right.