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A 5.0-cm-thick layer of oil (n = 1.46) is sandwiched between a 1.0-cm-thick sheet of glass and a 2.0-cm-thick sheet of polystyrene plastic (n = 1.59). How long (in ns) does it take light incident perpendicular to the glass to pass through this 8.0-cm-thick sandwich?

Answer :

aaregbe

Answer:

0.399 ns

Explanation:

In order to calculate the total time, the time taken for light to pass through each layer must be calculated and summed up. The time taken in each layer is:

t = d/v

where:

t is the time taken, d is the thickness of the layer, and v is the speed of light.

v = c/n

where:

c is the speed of sound and n is the refractive index.

[tex]t_{1} = \frac{d_{1}}{v_{1}} = \frac{d_{1}n_{1}}{c}[/tex] = 0.05*1.46/3*10^8 = 2.43*10^-10 s

[tex]t_{2} = \frac{d_{2}n_{2}}{c}[/tex] = 0.01*1.5/3*10^8 = 5*10^-11 s

[tex]t_{3} = \frac{d_{3}n_{3}}{c}[/tex] = 0.02*1.59/3*10^8 = 1.06*10^-10 s

total time = [tex]t_{1} +t_{2} + t_{3}[/tex] = 2.43*10^-10 + 5*10^-11 + 1.06*10^-10 = 0.399*10^-9 s = 0.399 ns

The time taken should be 0.399 ns.

Calculation of the time taken:

We know that

Time  taken = Thickness of the layer / speed of the light

Also,

v = speed of sound/refractive index.

Now

T1  = 0.05*1.46/3*10^8 = 2.43*10^-10 s

t2 = 0.01*1.5/3*10^8 = 5*10^-11 s

t3 = 0.02*1.59/3*10^8 = 1.06*10^-10 s

So,

total time is

=  2.43*10^-10 + 5*10^-11 + 1.06*10^-10 = 0.399*10^-9 s

= 0.399 ns

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