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To start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 54.0 degree above the horizontal. It explodes on the mountainside 36.0 s after firing. What are the x and y coordinates of the shell where it explodes, relative to its firing point? What is the x component of the acceleration?

Answer :

jolis1796

Answer:

x = 6136.478 m

y = 2089.2574m

aₓ = 0 m/s²

Explanation:

Given

v₀ = 290 m/s

∅ = 54°

t = 36 s

We can use the formulas

x = v₀*Cos ∅* t = (290 m/s)*Cos (54°)*(36 s) = 6136.478 m

y = y₀ + v₀*Sin ∅*t - 0.5*g*t²

⇒ y = 0 m + (290 m/s)*Sin (54°)*(36 s) - 0.5*(9.81 m/s²)*(36 s)² = 2089.2574m

aₓ = 0 m/s² since vₓ = v₀*Cos ∅ is a constant value.

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