Answered

a 1.5 v D-size battery stores 96kJ of energy. What steady current could it provide for 20 hours?

Answer :

elcharly64

Answer:

I=0.89 Amp

Explanation:

Electric Energy

When an electric power source has a voltage V, with a current I, the power it delivers is given by

[tex]P=V.I[/tex]

The electric energy is the product of the power by the time elapsed

[tex]E=P.t[/tex]

Replacing the first equation into the second

[tex]E=V.I.t[/tex]

The question provides the values for E, V, and t, let's solve the above equation for I

[tex]\displaystyle I=\frac{E}{V.t}[/tex]

The values are

[tex]E=96\ KJ = 96,000\ J, V = 1.5\ Volts, t = 20\ h = 20*3,600 = 72,000\ sec[/tex]

[tex]\displaystyle I=\frac{96,000\ J}{1.5\ V\times 72,000\ sec}[/tex]

[tex]\boxed{I=0.89\ Amp}[/tex]

Cricetus

The current it provide will be "0.89 Amp".

Current and Voltage:

Given that,

  • Voltage, V = 1.5 v
  • Energy, E = 96 kJ or, 96000 J
  • Time, t = 20 hours or, 72000 sec

We know the relation,

⇒ [tex]P=V.I[/tex] ...(equation 1)

and,

⇒ [tex]E = P.t[/tex] ...(equation 2)

From "equation 1" and "equation 2", we get

⇒ [tex]E = V.I.t[/tex]

Now

The Current be:

⇒ [tex]I = \frac{E}{V.t}[/tex]

By substituting the values,

      [tex]= \frac{96000}{1.5\times 72000}[/tex]

      [tex]= \frac{96000}{108000}[/tex]

      [tex]= 0.89 \ Amp[/tex]

Thus the above answer is right.

Find out more information about current and voltage here:

https://brainly.com/question/24858512

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