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Take a factor out of the square root:

a) √(10y²), where y<0

b) √(3y²), where y<0

Answer :

bayosanuade

Answer:

(a) [tex]-\sqrt{10}y[/tex]

(b) [tex]-\sqrt{3}y[/tex]

Step-by-step explanation:

(a) [tex]\sqrt{10y^{2}}[/tex] can also be written as [tex]\sqrt{10}[/tex] x [tex]\sqrt{y^{2}}[/tex]

the [tex]\sqrt{y^{2}}[/tex] = ± y

Therefore :

[tex]\sqrt{10y^{2}}[/tex] = ±[tex]\sqrt{10}y[/tex]

since it was given that y < 0 , then the factor will be [tex]-\sqrt{10}y[/tex]

(b) [tex]\sqrt{3y^{2}}[/tex] can also be written as : [tex]\sqrt{3}[/tex] x [tex]\sqrt{y^{2}}[/tex]

Therefore , one of the factor is [tex]-\sqrt{3}y[/tex]

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