FIND sin0 WHERE 0 IS THE ANGLE SHOWN. GIVE AN EXACT VALUE, NOT A DECIMAL APPROXIMATION. Branliest

Answer:
[tex]\frac{\sqrt{15} }{8}[/tex]
Step-by-step explanation:
We require to find the third side of the triangle.
Using Pythagoras' identity
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let x represent the third side, then
x² + 7² = 8², that is
x² + 49 = 64 ( subtract 49 from both sides )
x² = 15 ( take the square root of both sides )
x = [tex]\sqrt{15}[/tex]
Thus
sinΘ = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{\sqrt{15} }{8}[/tex]