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In 2008, Jen had a collection of 44 shells. In 2011, her collection had 107 shells. Enter a linear model which represents the number of shells, s, in Jen's collection t years after 2007?

Answer :

Answer:

s=23+21t

Step-by-step explanation:

Given, in 2008,Jen had a collection of 44 shells. In 2011 , her collection had 107 shells.

Increase of shells per year = [tex]\frac{(107-44)}{3}[/tex]=21

In 2007 , Jen had a collection of (44-21)=23 shells.

Therefore , the equation is

s=23+21t   [ t= year and s = no.of shells]

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