Answer :
Answer:
0.7864m
Explanation:
Ignore air resistance (the ball's horizontal speed stays constant), the time it takes for the ball to travel 1.95 m horizontally at the rate of 4.87 m/s.
t = 1.95 / 4.88 = 0.4s
This is also the time it takes to fall vertically with gravitational acceleration of g = 9.81 m/s2. We can use the following equation of motion to estimate the vertical distance:
[tex]h = gt^2/2[/tex]
[tex]h = 9.81*0.4^2/2 = 0.7864 m[/tex]
The height of the racquet ball is 0.8 m.
Since the ball hits the court at a horizontal distance of 1.95 m from the racquet, hence the range is 1.95 m.
Range = velocity * time
1.95 = 4.87 * t
t = 0.4 s
Hence it took 0.4 s for the ball to land. The height (h) is:
h = (1/2)gt²
but g = acceleration due to gravity = 10 m/s², hence:
h = (1/2)*10*0.4² = 0.8 m
Therefore the height of the racquet ball is 0.8 m.
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