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A 0.21 m3 drum contains 100L of a mixture ofseveral degreasing solvents in water.The concentraton oftrichloroethylen in the headspace( gas phase) above the water wasmeasured to be 0.00301 atm.The Henry's constant fortrichloroethylene is 0.00985atm.m3.mol-1 at25o.What is the concentration of tricholoroethylene inthe water in units of molarity? ( assume that the temperature ofthe solution is 25o)

Answer :

Answer:

The concentration is 6.42×10^-4 M

Explanation:

Number of moles trichloroethylene = pressure × volume/Henry's constant = 0.00301×0.21/0.00985 = 0.0642 mol

Volume of mixture = 100 L

Concentration of trichloroethylene = number of moles of trichloroethylene/volume of solution = 0.0642/100 = 6.42×10^-4 M

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