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43. Calculate the root mean square velocity (r.m.s.) of 1 mole of CO2 at 270C (mm = 44gmol-1

)

A. 4.12 x 102m/s

B. 12 x 102m/s

C. 5.2 x 102m/s

D. 1.2 x 102m/s​

Answer :

Answer:

5.2 x 102m/s

Explanation:

v(rms) = square root of 3RT divided molar mass in kg

        R =8.3J/molK     T = 543 kelvin

3(8.3)(543)/.044=307289  m^2/s^2    

square root 5.2X10^2 m/2  

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