Answered

A basketball is inflated to a pressure of 1.10 atm in a 28.0°C garage. What is the pressure of the basketball outside where the temperature is -2.00°C?

Answer :

arokoyuola

Answer:

0.99 atm

Explanation:

T1 = 28.0°C = 301.15°K

T2 = -2.0°C = 271.15°K

P1 = 1.10 atm

P2 = ?

P1/T1 = P2/T2

P2T1 = P1T2

P2 = P1T2/T1

P2 = 1.10*271.15/301.15

P2 = 0.99 atm

Other Questions