Answered

Assume a recent sociological report states that university students drink 4.10 alcoholic drinks per week on average, with a standard deviation of 1.7505. Suppose Jason, a policy manager at a local university, decides to take a random sample of 165 university students to survey them about their drinking habits. Determine the mean and standard deviation of the sampling distribution of the sample mean alcohol consumption. Provide your answer with precision to two decimal places.

Answer :

Answer:

a) Sample mean = 4.10 alcoholic drinks per week

b) Sample standard deviation = 0.14

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 4.10

Sample size, n = 125

Population standard deviation, σ = 1.7505

We have to estimate the following:

a) Sample mean alcohol consumption

[tex]\bar{x} = \mu = 4.10[/tex]

b) Standard deviation of the sampling distribution of the sample mean alcohol

[tex]s = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{1.7505}{\sqrt{165}} =0.13627 \approx 0.14[/tex]

Thus, the sample mean is 4.10 alcoholic drinks per week and sample standard deviation is 0.14 alcoholic drinks per week.

Other Questions