Answered

Cl2 + 2KBr - Br2 + 2KCI
How many grams of potassium chloride (KCl) can be produced from 356 g of
potassium bromide (KBr)?
223 g
814 g
149
479 g
US
10:09

Answer :

Amnda
The molar mass of potassium chloride is 74.5513g/mol, and the molar mass of potassium bromide is 119.002g/mol. You first need to find how many moles are in the given sample, so you divide the mass by the molar mass of potassium bromide. You don’t necessarily need to convert the mole ratio, since both the potassium chloride and potassium bromide have 2 moles in the chemical equation. Lastly, you multiply the moles at this point by the molar mass of potassium chloride, and you get your final answer.

Answer: 222.91g KCl
${teks-lihat-gambar} Amnda
samueladesida43

223 grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide.

HOW TO CALCULATE MASS:

  • According to this question, the following reaction is given:

  • Cl2 + 2KBr → Br2 + 2KCI

  • According to this equation, 2 moles of KBr will produce 2 moles of KCl.

  • First, we convert the mass of KBr to moles by dividing by its molar mass.

  1. Molar mass of KBr = 119g/mol
  2. Molar mass of KCl = 74.6g/mol

  • moles of KBr = 356g ÷ 119g/mol = 2.99mol

  • Since 2 moles of KBr will produce 2 moles of KCl, 2.99 moles of KBr will produce 2.99moles of KCl.

  • We then convert 2.99 moles of KCl to mass as follows:

  • mass of KCl = 2.99 moles × 74.6g/mol

  • mass of KCl = 223g.

  • Therefore, 223 grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide.

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