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An electron has a constant acceleration of +2.9 m/s2. At a certain instant its velocity is +8.6 m/s. What is its velocity (a) 2.1 s earlier and (b) 2.1 s later?

Answer :

Answer:

(a) = 2.51m/s

(b) = 14.69m/s

Explanation:

Given.

Velocity v = 8.6m/s

Acceleration a = 2.9m/s2

The final velocity of particle is given by

Vf = Vo+at

.(a) 8.6= Vo + (2.9)(2.1)

VP = 8.6 - (2.9)(2.1)= 2.51m/s

(b) Vf = 8.6+(2.9)(2.1) = 14.69m/s

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