Answer:
Efficiency: 0.4 (40%)
Explanation:
The efficiency of a simple machine is given by the ratio
[tex]\eta = \frac{W_{out}}{W_{in}}[/tex]
where
[tex]W_{in}[/tex] is the input work of the machine
[tex]W_{out}[/tex] is the output work of the machine
For the machine in this problem, we have:
[tex]W_{out}=800 J[/tex] is the output work
[tex]W_{in}=2000 J[/tex] is the input work
Therefore, the efficiency of the machine is
[tex]\eta=\frac{800}{2000}=0.4[/tex]
Which can be also written as percentage:
[tex]\eta=0.4\cdot 100 = 40\%[/tex]
Efficiency is defined as the ratio of output and input work. The efficiency of a machine will be 0.4 (40%)
Efficiency is defined as the ratio of output and input work. Efficiency relates to how close we can get to a certain output from a given input with the least amount of waste.
The given data in the problem is;
W₀ is the work output = 800 J
[tex]\rm W_i[/tex] is the work input = 2,000 J
[tex]\rm \eta[/tex] is the efficiency of a machine=?
[tex]\rm \eta = \frac{W_o}{W_i} \\\\ \rm \eta = \frac{800}{2000} \\\\ \rm \eta = 0.4[/tex]
Efficiency in the terms of percentage;
[tex]\rm \eta = 0.4 \times 100 = 40[/tex] %
Hence the efficiency of a machine will be 0.4 (40%)
To learn more about the efficiency refer to the link;
https://brainly.com/question/6672666
