Answered

What is the dissociation constant, K d , of a ligand with a percent occupancy, or fractional saturation, of 30 % when [ligand] = 10 − 7 M ?

Answer :

Answer : The value of dissociation constant is, [tex]2.33\times 10^{-7}[/tex]

Explanation :

Formula used :

[tex]\nu=\frac{[A]}{k_d+[A]}[/tex]

where,

[tex]\nu[/tex] = percent occupancy = 30 % = 0.3

[A] = consecration of unbound ligands = [tex]10^{-7}M[/tex]

[tex]k_d[/tex] = dissociation constant = ?

Now put all the given values in the above formula, we get:

[tex]0.3=\frac{10^{-7}}{k_d+10^{-7}}[/tex]

[tex]k_d=2.33\times 10^{-7}[/tex]

Thus, the value of dissociation constant is, [tex]2.33\times 10^{-7}[/tex]

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