Answer :
Answer : The specific heat of this substance is, 1.13 J/g.K
Explanation :
Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.
As we are given that the chemical formula of compound is, [tex]C_2H_6SO[/tex]
First we have to calculate the molar mass of given compound.
Molar mass of [tex]C_2H_6SO[/tex] = [tex]2(12g/mol)+6(1g/mol)+32g/mol+16g/mol[/tex]
Molar mass of [tex]C_2H_6SO[/tex] = 78 g/mol
Now we have to calculate the specific heat of this substance.
Specific heat of this substance = [tex]\frac{\text{Molar heat capacity of a compound}}{\text{Molar mass of }C_2H_6SO}[/tex]
Specific heat of this substance = [tex]\frac{88.0J/mol.K}{78g/mol}[/tex]
Specific heat of this substance = 1.13 J/g.K
Thus, the specific heat of this substance is, 1.13 J/g.K
The specific heat capacity of the compound with a molar heat capacity of 88.0 J/mol-K is 1.13 J/g-K.
HOW TO CALCULATE SPECIFIC HEAT CAPACITY:
- Molar heat capacity is defined as the amount of heat needed by one mole of a substance to raise its temperature by one degree Celsius.
- The specific heat capacity of a substance can be calculated by dividing the molar heat capacity by the molar mass of the substance.
- Molar mass of C2H6SO = 12(2) + 1(6) + 32 + 16 = 78g/mol
- Specific heat capacity = 88.0 J/mol-K ÷ 78 g/mol
- Specific heat capacity = 1.13 J/g-K.
- Therefore, the specific heat capacity of the compound with a molar heat capacity of 88.0 J/mol-K is 1.13 J/g-K.
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