Answer:
V(t)=50⋅(2.5) ^t
Step-by-step explanation:
Since the initial number of views is 50, the function that best models the number of views months after it's uploaded is V(t)=50⋅(2.5) ^t
The model V(t)=50 × [tex]2.5^{t}[/tex] represents the best approximation that fits the data.
Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.
In other words, an equation is a set of variables that are constrained through a situation or case.
If we look at the behavior of data then we can see that views are exponential increasing with time so it gives the idea that variable t should be in the power of something.
By the first data 50, it is clear that the formation should be like
V(t) = 50[tex]x^{t}[/tex] so when we put t = 0 it comes out to be 50.
Now, substitute the following data
313 = 50x²
x² = 313/50⇒ x = 2.50
Hence V(t)=50 × [tex]2.5^{t}[/tex] will be the correct model.
For more about the equation,
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