Answer :
Answer:
Sin(P)=p/q
Sin(R)=r/q
Step-by-step explanation:
The given question is INCOMPLETE.
which sine ratios are correct for ∆PQR? Check all that apply
sin(p)=r/q
sin(p)=p/q
sin(q)=r/p
sin(r)=q/r
sin(r)=r/q
Now, as we know in any right angled triangle:
[tex]Sin (\theta) = \frac{Perpendicular}{Hypotenuse}[/tex]
Now, here in ∆PQR
If we consider angle P, then QR = p is Perpendicular.
[tex]Sin (P) = \frac{Perpendicular}{Hypotenuse} = \frac{p}{q}[/tex]
If we consider angle R, then PQ = r is Perpendicular.
[tex]Sin (R) = \frac{Perpendicular}{Hypotenuse} = \frac{r}{q}[/tex]
Hence, sin(p)=p/q and sin(r)=r/q are the ONLY correct options.
