Answer :
Answer:
a) Maximum velocity of the object = 0.335 m/s
b) Kinetic energy at maximum velocity = 0.000563 J = 5.63 × 10⁻⁴ J
Explanation:
Given that the
K = spring's force constant = 1.25 N/m
m = 0.01 Kg
The maximum position from equilibrium = amplitude = A = 3 cm = 0.03 m
The displacement of any body experiencing this type of motion is given as
x = A cos wt
where w = angular frequency = √(k/m) = √(1.25/0.01) = 11.18 rad/s
t = time
a) velocity of motion can be obtained from the displacement
v = dx/dt
x = A cos wt
v = dx/dt = - Aw sin wt
Maximum velocity = Aw = 0.03 × 11.18 = 0.335 m/s
b) Kinetic energy = mv²/2 = 0.01 × 0.335²/2 = 0.000563 J = 5.63 × 10⁻⁴ J