Your school wants to take out an ad in the paper congratulating the basketball team on a successful season, as shown to the right. The area of the photo will be half the area of the entire ad. What is the value of x?

Answer:
[tex](7 - x)(4 - x) \\ 28 - 7x - 4x + x {}^{2} \\ x {}^{2} - 11x + 28 = 0 \\ x {}^{2} - 7x - 4x + 28 = 0 \\ x (x - 7) - 4(x - 7 )= 0 \\ (x - 4)(x - 7) = 0 \\ [/tex]
the value of x is 7 or 4
Answer:
2.13
Step-by-step explanation:
You need to write an equation that models the situation. Make sure you use the properties of equality to change the equation into a standard form.