Answer :
Explanation:
The reaction equation will be as follows.
[tex]HCl + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]
In this reaction, breakage of hydrogen and chlorine bond takes place whereas the formation of O-H bond takes place.
Therefore, enthalpy of the reaction will be calculated as follows.
[tex]\Delta H = \Delta H_{\text{bond broken}} - \Delta H_{\text{bond formed}}[/tex]
= [tex]\Delta H_{HCl} - \Delta H_{O-H}[/tex]
= 432 kJ/mol - 464 kJ/mol
= -32 kJ/mol
Negative sign indicates that heat is liberating.
Thus, we can conclude that the given reaction is exothermic in nature and net enthalpy change is 32 kJ/mol.