Answer :
Answer:
The formula to find the perimeter of a rectangle is 2*length + 2*width
2(2x+1)+2(x^2+2x-1)
First we want to distribute the 2 through both the length and the width
(4x+2) + (2x^2+4x-2)
After we distributed the 2 through like we did up above, we now want to add them together to find the perimeter.
We want to combine all like terms
2x^2, doesn't combine with anything so we leave it the same
4x+4x=8x, add the coefficients and leave the variable
2-2=0, we just leave that out, don't do anything with it
What we have left is:
2x^2+8x,
Which would be C), if the answer is 2x to the second power+8x,
Hope this helps ;)
The perimeter of the rectangle is [tex]2x^2+8x[/tex]. All options are incorrect.
Given:
The length of the rectangle is [tex]2x+1[/tex].
The width of the rectangle is [tex]x^2+2x-1[/tex].
To find:
The equation for the perimeter of the rectangle.
Explanation:
Perimeter of a rectangle is:
[tex]P=2(l+w)[/tex]
Where, [tex]l[/tex] is length and [tex]w[/tex] is width.
Using the above formula the perimeter of the rectangle is;
[tex]P=2((2x+1)+(x^2+2x-1))[/tex]
[tex]P=2(x^2+4x)[/tex]
[tex]P=2(x^2)+2(4x)[/tex]
[tex]P=2x^2+8x[/tex]
Therefore, the perimeter of the rectangle is [tex]2x^2+8x[/tex] and all options are incorrect.
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