Consider the gas-phase reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g), for which Kp = 32 at 500 K. If the mixture is analyzed and found to contain 0.19 bar of Cl2, 0.29 bar of Br2 and 1.4 bar of BrCl, describe the situation:a) Q > K and more reactants will be made to reach equilibrium.b) Q > K and more products will be made to reach equilibrium.c) Within 1 decimal place, Q = K and the reaction is at equilibriumd) Q < K and more products will be made to reach equilibrium.e) Q < K and more reactants will be made to reach equilibrium.

Answer :

Edufirst

Answer:

  • a) Q > K and more reactants will be made to reach equilibrium

Explanation:

The reaction quotient, Q, is the actual ratio of concentrations or pressure of products to reactants.

When Q is equal to the equilibrium constant, the reaction is at equilibrium.

When Q > K, the concentrations, or pressures, of the products will have to decrease to reach the equilibrium, thus more reactants will be made.

When Q < K the concentrations, or pressures, of the reactants will have to decrease to reach the equilibrium, thus more products will be made.

Calculate Q:

  • Reaction equation: Cl₂(g) + Br₂(g) ⇄ 2 BrCl(g),

         [tex]P_{Cl_2}}=0.19bar\\\\P_{Br_2}}=0.29bar\\\\P_{BrCl}=1.4bar[/tex]

        [tex]Q=\dfrac{(P_{BrCl})^2}{(P_{Br_2}).(P_{Cl_2})}[/tex]

        [tex]Q=\dfrac{(1.4bar)^2}{(0.19bar).(0.29bar)}[/tex]

        [tex]Q\approx 36[/tex]

Therefore, since Q > K, the pressure of the products should decrease to reach the equilibrium, meaning that more reactants will be made, i.e. option a).

The mixture is analyzed and found to contain 0.19 bar of Cl2, 0.29 bar of Br2 and 1.4 bar of BrCl, the situation will be Q > K and more reactants will be made to reach equilibrium.

What is gas-phase reaction?

The reaction occur in gas phase are called gas phase reaction.

Given reaction is

[tex]\rm Cl_2(g) + Br_2(g) <=> 2 BrCl(g)[/tex]

[tex]Cl_2 = 0.19\; bar\\\\Br_2=0.29 \;bar\\\\BrCl = 1.4\;bar[/tex]

Calculating the value of Q

[tex]Q = \dfrac{(P_B_r_C_l)^2}{(P_B_r_2)(P_C_l_2)} \\\\Q =\dfrac{(1.4\;bar)^2}{(0.29\;bar)( 1.9\;bar)}\\\\Q= 36[/tex]

Thus, the correct option is (a), Q > K and more reactants will be made to reach equilibrium.

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