Answered

In a baseball game, a batter hits the 0.150-kg ball straight back at the pitcher at 180 km/h .

If the ball is traveling at 160 km/h just before it reaches the bat, what is the magnitude of the average force exerted by the bat on it if the collision lasts 5.0 ms ?

F = ?

Answer :

Answer: F = 0.17N

Explanation: From the Newton second law of motion.

F= m(v-u)/t.

V=180km/hr = 180×1000/3600= 50m/s

U= 160km/hr = 160×1000/3600= 44.44m/s

t= 5secs

F=m(v-u)/t

F= 0.150(50-44.44)/5

F=0.150×5.56/5

F= 0.835/5

F= 0.17N rounded to two decimal places.

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