Answer :
Answer:
[tex]\large \boxed{\text{17.59 MeV}}[/tex]
Explanation:
[tex]\rm _{1}^{2}\text{H} + \, _{1}^{3}\text{H} \longrightarrow \, _{2}^{4}\text{He} + \,_{0}^{1}\text{n} + E[/tex]
1. Calculate the mass difference
Mass of ₁²H = 2.014 102 u
Mass of ₁³H = 3.016 049
Total = 5.030 151 u
Mass of ₂⁴He = 4.002 603
Mass of ₀¹n = 1.008 665
Total = 5.011 268
Difference = 0.018 883 u
2. Convert the mass difference to energy.
931.5 MeV = 1 u
[tex]\text{Energy} = \text{0.018 883 u} \times \dfrac{\text{931.5 MeV}}{\text{1 u}} = \textbf{17.59 MeV}\\\\\text{The energy released is $\large \boxed{\textbf{17.59 MeV}}$}[/tex]