Answer:
see attachment
Step-by-step explanation:
We want to choose the graph that represents:
[tex]y = \sqrt[3]{x} + 2[/tex]
We know the parent function will be:
[tex]y = \sqrt[3]{x} [/tex]
There has been a vertical shift upward by 2 units.
Therefore the graph of
[tex]y = \sqrt[3]{x} + 2[/tex]
is obtained by shifting the parent function up 2 units.
Its y-intercept will move from 0 to 2.
The graph is shown in attachment.
Note: since, you forgot to add the graph, but I have solved your query in terms of explaining the graph of the described function which will anyways clear your concept.
Answer:
The graph of this function is also attached below.
Step-by-step explanation:
Given the function
[tex]y=\sqrt[3]{x}+2[/tex]
[tex]\mathrm{Domain\:of\:}\:\sqrt[3]{x}+2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:<x<\infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}[/tex]
[tex]\mathrm{Range\:of\:}\sqrt[3]{x}+2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:<f\left(x\right)<\infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}[/tex]
[tex]\mathrm{Axis\:interception\:points\:of}\:\sqrt[3]{x}+2:\quad \mathrm{X\:Intercepts}:\:\left(-8,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:2\right)[/tex]
[tex]\mathrm{Asymptotes\:of}\:\sqrt[3]{x}+2:\quad \mathrm{None}[/tex]
[tex]\mathrm{Extreme\:Points\:of}\:\sqrt[3]{x}+2:\quad \mathrm{Saddle}\left(0,\:2\right)[/tex]
The graph of this function is also attached below.
