Answer :
9514 1404 393
Answer:
30,500 ft·lb
Step-by-step explanation:
The 3000 lb ball is raised 10 ft, so (3000 lb)·(10 ft) = 30,000 ft·lb is the work done on it.
The weight of the cable is (10 ft)·(10 lb/ft) = 100 lb. Its center of mass is at its midpoint, 5 ft above the ground. When all of the cable is raised to a height of 10 ft above the ground, that center of mass is elevated 5 ft. The work done on the cable is ...
(100 lb)·(5 ft) = 500 ft·lb
The total work done on the ball and cable is ...
30,000 ft·lb +500 ft·lb = 30,500 ft·lb