Jadashy00
Answered

(I NEED THIS ANSWERED QUICKLY! I WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!)

An airplane is flying at a height of 3.7 kilometers on a path that will take it directly over the airport. At a certain instant its slant distance from the airport is 14.2 kilometers. How far must the plane travel to be directly above the airport?

A. √187.95
B. √189.95
C. √188.95
D. √185.95

Answer :

calculista

Answer:

Option A [tex]\sqrt{187.95}\ Km[/tex]

Step-by-step explanation:

we know that

Applying the Pythagorean Theorem

[tex]c^2=a^2+b^2[/tex]

where

c is the greater side (the hypotenuse)

a and b are the legs

we have

[tex]a=3.7\ Km[/tex] ----> the height of the airplane

[tex]c=14.2\ Km[/tex] ---> slant distance from the airport

substitute

[tex]14.2^2=3.7^2+b^2[/tex]

solve for b

[tex]b^2=14.2^2-3.7^2[/tex]

[tex]b^2=187.95[/tex]

[tex]b=\sqrt{187.95}\ Km[/tex]

Answer:

a

Step-by-step explanation:

Other Questions