Answer :
Answer:
8 time increase in K.E.
Explanation:
Consider Mass of truck = m kg and speed = v m/s then
K.E. = 1/2 ×mv²
If mass and speed both are doubled i.e let m₀ = 2m and v₀ = 2v then
(K.E.)₀ = 1/2 ×2m(2v)²
(K.E.)₀ = 8 (1/2 × mv²) = 8 × K.E.
The kinetic energy of the truck when loaded so that its mass and its speed are both doubled is 8 times the K.E.
Given the following data:
- Velocity = 10 km/h
To determine the kinetic energy of the truck when loaded so that its mass and its speed are both doubled:
When its mass and speed are both doubled, we have:
- Mass = 2M
- Velocity = 2V
Mathematically, kinetic energy is calculated by using the formula;
[tex]K.E = \frac{1}{2} MV^2[/tex]
Where:
- K.E is the kinetic energy.
- M is the mass of an object.
- V is the velocity of an object.
Substituting the given parameters into the formula, we have;
[tex]K.E = \frac{1}{2} \times 2M \times (2V)^2\\\\K.E = \frac{1}{2} \times 2M \times 4V^2\\\\K.E = \frac{1}{2} \times 8MV^2\\\\K.E = 8 \times \frac{1}{2} MV^2[/tex]
Therefore, the kinetic energy of the truck when loaded so that its mass and its speed are both doubled is 8 times the K.E.
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