Answer :
Answer:
Final volume: 35 L, final pressure: 0.88 atm
Explanation:
I assume there is a typo in the question: the volume of the gas tank is constant, so the question is "what is the new pressure in the tank?"
Since the volume of the gas is constant, we can use the pressure's law, which states that:
"For an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"
Mathematically:
[tex]\frac{p}{T}=const.[/tex]
where
p is the gas pressure
T is the absolute temperature
The equation can be rewritten as
[tex]\frac{p_1}{T_1}=\frac{p_2}{T_2}[/tex]
where in this problem:
[tex]p_1=1 atm[/tex] is the initial pressure
[tex]T_1=27^{\circ}C+273=300 K[/tex] is the initial temperature
[tex]T_2=-10^{\circ}C+273=263 K[/tex] is the final temperature
Therefore, the new pressure is
[tex]p_2=\frac{p_1 T_2}{T_1}=\frac{(1)(263)}{300}=0.88 atm[/tex]
While the final volume is still 35 L.