Answer :

Answer:

The answer to your question is  x = 8[tex]\sqrt{2}[/tex]    or 11.31

Step-by-step explanation:

To solve this problem need to use trigonometric functions

The trigonometric function that relates the opposite side and the hypotenuse is sine.

           sin [tex]\alpha = \frac{8}{x}[/tex]

- Solve for x

           x = 8/sin 45

- sin 45 = 1/[tex]\sqrt{2}[/tex]

- Find x

           x = 8 / 1/[tex]\sqrt{2}[/tex]

          x = 8[tex]\sqrt{2}[/tex]    or 11.31

           

ANSWER ➺

[tex]x=8\sqrt{2}[/tex]

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[tex]Cos0=\frac{adjacent}{hypotenuse}[/tex]

[tex]Cos45^o=\frac{8}{x}[/tex]

[tex]\frac{1}{\sqrt{2} } =\frac{8}{x}[/tex]

[tex]x=8\sqrt{2}[/tex]

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hope it helps..

have a great day!!