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Find any points of discontinuity for the rational function. y =
A. x = 6, x = 2, x = 8
B. x = 9 x = 7
C. x = –9, x = –7
D. x = –6, x = –2, x = –8

Find any points of discontinuity for the rational function. y = A. x = 6, x = 2, x = 8 B. x = 9 x = 7 C. x = –9, x = –7 D. x = –6, x = –2, x = –8 class=

Answer :

calculista

Answer:

Option C. x = –9, x = –7

Step-by-step explanation:

we know that

In the rational function, the denominator cannot be equal to zero

so

In this problem

we have that the denominator is equal to

[tex](x+9)(x+7)[/tex]

equate to zero

[tex](x+9)(x+7)=0[/tex]

so

The solutions is  x=-9 and x=-7

so

For x=-7 or x=-9 the denominator is equal to zero

therefore

x=-9, x=-7 are points of discontinuity for the rational function given

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