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An automobile’s velocity starting from a complete stop is v(t) = 140t/ 5t+3 where v is measured in feet per second.
What happens to the auto’s velocity as time increases?

Answer :

noahkanatzar

Answer:

velocity increases with time

A direct relationship which implies as the time increases, the velocity also increase.

Data;

  • v(t) = 140t / 5t+3

Velocity of the Car

From the equation given, increase in time (t) of the car will lead to an increase in the velocity. They have a direct relationship which implies that the value of the velocity is dependent on the time.

An example of this,

let t = 2

[tex]v(t) = \frac{140t}{5t + 3}\\ v(2) = \frac{280}{5(2) + 3}\\ v(2) = \frac{280}{13}\\v(2) = 21.54[/tex]

Let t = 5

[tex]v(t) = \frac{140t}{5t + 3} \\v(5) = \frac{140(5)}{5(5) + 3} \\v(5) = 25[/tex]

let t = 3

[tex]v(t)= \frac{140t}{5t + 3} \\v(3) = \frac{140(3)}{5(3) + 3} = 23.3[/tex]

From the above, this shows a direct relationship which implies as the time increases, the velocity also increase.

Learn more on direct proportionality here;

https://brainly.com/question/12970676

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