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Logan wants to mix a17% acid solution with a 41% acid solution to get 14 L of a 36% acid solution. How many liters of the 17% solution and how many liters of the 41% solution should be mixed?

Answer :

Answer: The volume of acid required from 17 % solution and that from 41 % solution is 2.92 L and 11.08 L respectively

Explanation:

We are given:

Total volume of the acid solution = 14 L

Let the volume of 17 % acid solution to be added is 'x' L

So, the volume of 41 % acid solution will be = (14 - x) L

Acid solution to be made = 14 L of  36 % acid solution

Evaluating the value of 'x'

[tex]\Rightarrow (17\% \text{ of }x)+(41\% \text{ of }(14-x))=36\%\text{ of }14\\\\\Rightarrow (\frac{17}{100}\times x)+(\frac{41}{100}\times (14-x))=\frac{36}{100}\times 14\\\\\Rightarrow x=2.92L[/tex]

Volume of acid of 17 % solution required = x = 2.92 L

Volume of acid of 41 % solution required = (14 - x) = (14 - 2.92) L = 11.08 L

Hence, the volume of acid required from 17 % solution and that from 41 % solution is 2.92 L and 11.08 L respectively

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