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1) Of the following transitions in the Bohr hydrogen atom, the __________ transition results in the emission of the highest-energy photon. A) n = 1 → n = 6 B) n = 6 → n = 1 C) n = 6 → n = 3 D) n = 3 → n = 6 E) n = 1 → n = 4

Answer :

Answer:

B. n = 6 → n = 1

Explanation:

B: n=6, n=1 is highest-energy photon. Emission is going from a higher energy level down to a lower energy level, so that will rule out a,d,e. So between b and c, it will be b because if you study the n=1 energy level you will see that it is the ground state energy level, which means that energy is the greatest in this energy level.

The transition in the Bohr hydrogen atom that results in the emission of the highest-energy photon is n = 6 → n = 1.

According to the Bohr's model of the atom, an electron moves from a lower to a higher energy level when it absorbs energy. The electron is unstable in this excited or higher energy state so it quickly returns to ground state.

The energy given off is equal to the energy difference between the energy levels. The greater the difference in energy between the energy levels, the greater the energy given off. Therefore, the transition in the Bohr hydrogen atom that results in the emission of the highest-energy photon is n = 6 → n = 1.

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