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A low-pressure sodium vapor lamp whose wavelength is 5.89 x 10−7 m passes through double-slits that are 2.0 x 10−4 m apart and produces an interference pattern whose fringes are 3.2 x 10−3 m apart on the screen. What is the distance to the screen?

Answer :

fnej

Answer:

1.1 meters

Explanation:

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Given,

β = 3.2 × [tex]10^{-3}[/tex] m

λ = 5.89 × [tex]10^{-7}[/tex] m

d = 2 × [tex]10^{-4}[/tex] m

According to fringe width on Young's double slit experiment

β = λL/d

L = dβ/λ

L = 2 × [tex]10^{-4}[/tex] m × 3.2 × [tex]10^{-3}[/tex] m / 5.89 × [tex]10^{-7}[/tex] m

L = 1.1m

What is fringe width formula?

The distance between any two consecutive dark or bright fringes and all the fringes are of equal lengths. Fringe width is given by, β = D/dλ. The angular width, Ө = λd = βD.

What is meant by Young's double-slit experiment?

When monochromatic light passing through two narrow slits illuminates a distant screen, a characteristic pattern of bright and dark fringes is observed.

Learn more about Young's Double Slit Experiment here

https://brainly.com/question/17275496

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