Answer :
Answer:
17.63W
Explanation:
The total energy supplied to the ice is used to melt the ice. Since the ice starts to melt at [tex]0^oC[/tex] and also melts completely at the same temperature, the latent heat of fusion will be the focus in solving this problem.
Latent heat of fusion [tex]H_f[/tex] is defined as the amount of energy that changes a solid substance to liquid state without any change in temperature. It is given by the following relationship;
[tex]H_f=ml.....................(1)[/tex]
where m is the mass of the substance and l is the specific latent heat of fusion of the substance.
The specific latent heat of fusion of ice is [tex]334000J/kg[/tex] approximately.
The total heat supplied to the ice was used to melt the ice and is calculated using equation (1), given that m = 4.56kg.
[tex]H_f=4.56*334000\\H_f=1523040J[/tex]
The total energy supplied to the ice is equivalent to the average power P entering the ice multiplied by the time t for which the power is supplied. Therefore;
[tex]P *t=1523040..............(2)[/tex]
where t = 1 day and 1 day = 24 hours.
24 hours = 60 x 60 x 24s =86400s.
Hence, t = 86400s.
Substituting into equation (2), we get the following;
[tex]P*86400=1523040[/tex]
[tex]P=\frac{1523040}{86400}\\P=17.63W[/tex]