Option C: [tex]64 \ cm^2[/tex] is the area of the composite figure.
Explanation:
It is given that the composite figure is divided into two congruent trapezoids.
The measurements of both the trapezoids are
[tex]b_1=10 \ cm[/tex]
[tex]b_2=6 \ cm[/tex] and
[tex]h=4 \ cm[/tex]
Area of the trapezoid = [tex]\frac{1}{2} (b_1+b_2)h[/tex]
Substituting the values, we get,
[tex]A=\frac{1}{2} (10+6)4[/tex]
[tex]A=\frac{1}{2} (16)4[/tex]
[tex]A=32 \ cm^2[/tex]
Thus, the area of one trapezoid is [tex]$32 \ {cm}^{2}$[/tex]
The area of the composite figure can be determined by adding the area of the two trapezoids.
Thus, we have,
Area of the composite figure = Area of the trapezoid + Area of the trapezoid.
Area of the composite figure = [tex]$32 \ {cm}^{2}+32 \ {cm}^{2}$[/tex] [tex]= 64 \ cm^2[/tex]
Thus, the area of the composite figure is [tex]64 \ cm^2[/tex]
Hence, Option C is the correct answer.
Answer:
64 cm like the other person said ;/
Step-by-step explanation:
