Answer:
[tex]x=-1 or x=5[/tex]
Step-by-step explanation:
let the number be 'x'.
According to the statement given above:
[tex]x^2-5=4x[/tex]
or
[tex]x^2-4x-5=0[/tex]
Factorizing the quadratic equation for 'x'
[tex]x^2+x-5x-5=0[/tex]
Taking common from the equation:
[tex]x(x+1)-5(x+1)=0\\(x+1)(x-5)=0\\(x+1)=0, (x-5)=0\\x=-1,x=5[/tex]
The solution of the equation is [tex]x=-1 or x=5[/tex]