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An especially violent lightning bolt has an average current of 1.89 x 103 A lasting 0.133 s. How much charge is delivered to the ground by the lightning bolt?

Answer :

Charge = 25.9 [tex]Ampsec^{-1}[/tex]

Explanation:

Given,

The average current (I) = [tex]{1.89} \times {103 A}[/tex] and

Time period (T) = 0.133 s

The charge is calculated by multiplying the current to the time period.

Hence,

To find, the charge delivered to the ground by the lightning bolt(Q) = ?

By applying the formula of charge that is-

Charge(Q) = [tex]Current(I) \times Time(T)[/tex]

∴ Charge(Q) = [tex]{1.89} \times {103 A}[/tex][tex]\times 0.133 s[/tex]

= 25.89111 [tex]As^{-1}[/tex]

= 25.9 [tex]As^{-}[/tex]

Thus, the charge of 25.9 [tex]Ampsec^{-1}[/tex] is delivered to the ground by the lightning bolt.

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