Answer :
Answer:
A, B, and E
Explanation:
The springs are identical, and are compressed the same amount, so they have the same initial elastic potential energy. (E is true)
Energy is conserved, so the darts have the same amount of kinetic energy. (A is true, C is false)
The lighter dart has the same energy as the heavier dart. Since it has less mass, it must have a greater speed. (B is true, D is false)
Even though those who move away from the spring, this same darts have always had the similar K.E. The lightweight dart accelerates away from the spring speedier than just the heavier dart. The elastic potential of both darts was the same from the start.
- Whenever two springs are squeezed by some of the similar amount (x), their Elastic potential energy is equivalent.
→ [tex]Darts \ K.E = \frac{1}{2} m_1 v_1^2[/tex]
and,
[tex]= \frac{1}{2} m_2v_2^2[/tex]
- As nothing more than a result, the kinetic energy of the corresponding darts are therefore equal to [tex]\frac{1}{2} kx^2[/tex] since their springs as well as compressions would be the similar.
→ [tex]\frac{1}{2} m_1 v_1^2 = \frac{1}{2} m_2v_2^2[/tex]
and,
→ [tex]\frac{1}{2} m_2 v_2^2 = \frac{1}{2} kx^2[/tex]
This demonstrates that perhaps the lighter dart will have to go quickly than the bulkier dart.
Thus the above response is right.
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