Answer :
Answer:
Part A
1. [tex]0.04[/tex]
2. [tex]0.51[/tex]
3. [tex]0.55[/tex]
Part B
1. [tex]0.04[/tex]
2.[tex]0.85[/tex]
3.[tex]0.97[/tex]
4.[tex]0.37[/tex]
Explanation:
Given ,
Percentage of American with blood group O - [tex]45[/tex] %
Percentage of American with blood group A - [tex]40[/tex] %
Percentage of American with blood group B - [tex]11[/tex] %
Percentage of American with blood group AB - [tex]4[/tex] %
Part A
Probability that donor
1.has Type AB blood
[tex]= 1- 0.45-0.4-0.11\\= 4[/tex]
2.has Type A or Type B
[tex]0.4+0.11\\= 0.51[/tex]
3.is not Type O?
[tex]1 -[/tex] Probability of type (O)
[tex]1 - 0.45\\0.55[/tex]
Part B
1. Type O?
[tex]0.45 * 0.45 * 0.45 * 0.45 \\= 0.04[/tex]
2.no one is Type AB?
[tex](1-0.04)^4\\0.96^4\\0.85[/tex]
3.they are not all Type A?
[tex]1-(0.4)^4\\0.97[/tex]
4.at least one person is Type B?
[tex]1- (1-0.11)^4\\1-0.63\\0.37[/tex]